(2b-5)(b^2-14b+40)=0

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Solution for (2b-5)(b^2-14b+40)=0 equation: 


Simplifying
(2b + -5)(b2 + -14b + 40) = 0

Reorder the terms:
(-5 + 2b)(b2 + -14b + 40) = 0

Reorder the terms:
(-5 + 2b)(40 + -14b + b2) = 0

Multiply (-5 + 2b) * (40 + -14b + b2)
(-5(40 + -14b + b2) + 2b * (40 + -14b + b2)) = 0
((40 * -5 + -14b * -5 + b2 * -5) + 2b * (40 + -14b + b2)) = 0
((-200 + 70b + -5b2) + 2b * (40 + -14b + b2)) = 0
(-200 + 70b + -5b2 + (40 * 2b + -14b * 2b + b2 * 2b)) = 0
(-200 + 70b + -5b2 + (80b + -28b2 + 2b3)) = 0

Reorder the terms:
(-200 + 70b + 80b + -5b2 + -28b2 + 2b3) = 0

Combine like terms: 70b + 80b = 150b
(-200 + 150b + -5b2 + -28b2 + 2b3) = 0

Combine like terms: -5b2 + -28b2 = -33b2
(-200 + 150b + -33b2 + 2b3) = 0

Solving
-200 + 150b + -33b2 + 2b3 = 0

Solving for variable 'b'.

The solution to this equation could not be determined.

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